(-1/2)(b-4)-4=18

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Solution for (-1/2)(b-4)-4=18 equation:



(-1/2)(b-4)-4=18
We move all terms to the left:
(-1/2)(b-4)-4-(18)=0
Domain of the equation: 2)(b-4)!=0
b∈R
We add all the numbers together, and all the variables
(-1/2)(b-4)-22=0
We multiply parentheses ..
(-1b^2-1/2*-4)-22=0
We multiply all the terms by the denominator
(-1b^2-1-22*2*-4)=0
We get rid of parentheses
-1b^2-1-4-22*2*=0
We add all the numbers together, and all the variables
-1b^2=0
a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-2}=0$

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