(-1/2)(b-4)-4=18

Solution for (-1/2)(b-4)-4=18 equation:

(-1/2)(b-4)-4=18

We move all terms to the left:

(-1/2)(b-4)-4-(18)=0


Domain of the equation: 2)(b-4)!=0

b∈R


We add all the numbers together, and all the variables

(-1/2)(b-4)-22=0

We multiply parentheses ..

(-1b^2-1/2*-4)-22=0

We multiply all the terms by the denominator


(-1b^2-1-22*2*-4)=0

We get rid of parentheses

-1b^2-1-4-22*2*=0

We add all the numbers together, and all the variables

-1b^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{-2}=0$