(-1/2)*w-(3/5)=(1/5)*2

Solution for (-1/2)*w-(3/5)=(1/5)*2 equation:

(-1/2)*w-(3/5)=(1/5)*2

We move all terms to the left:

(-1/2)*w-(3/5)-((1/5)*2)=0


Domain of the equation: 2)*w!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

(-1/2)*w-(+3/5)-((+1/5)*2)=0

We multiply parentheses

-1w^2-(+3/5)-((+1/5)*2)=0

We get rid of parentheses

-1w^2-3/5-((+1/5)*2)=0

We calculate fractions


-1w^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{-2}=0$