(-1/2)*w-(3/5)=(1/5)*w

Solution for (-1/2)*w-(3/5)=(1/5)*w equation:

(-1/2)*w-(3/5)=(1/5)*w

We move all terms to the left:

(-1/2)*w-(3/5)-((1/5)*w)=0


Domain of the equation: 2)*w!=0

w!=0/1

w!=0

w∈R



Domain of the equation: 5)*w)!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

(-1/2)*w-((+1/5)*w)-(+3/5)=0

We multiply parentheses

-1w^2-((+1/5)*w)-(+3/5)=0

We get rid of parentheses

-1w^2-((+1/5)*w)-3/5=0

We calculate fractions


-1w^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{-2}=0$