(-1/2x+3)(1-10x)=0

Solution for (-1/2x+3)(1-10x)=0 equation:

(-1/2x+3)(1-10x)=0


Domain of the equation: 2x+3)(1-10x)!=0

x∈R


We add all the numbers together, and all the variables

(-1/2x+3)(-10x+1)=0

We multiply parentheses ..

(+10x^2-1x-30x+3)=0

We get rid of parentheses

10x^2-1x-30x+3=0

We add all the numbers together, and all the variables

10x^2-31x+3=0

a = 10; b = -31; c = +3;
Δ = b2-4ac
Δ = -312-4·10·3
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-29}{2*10}=\frac{2}{20}
=1/10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+29}{2*10}=\frac{60}{20}
=3
$