(-1/3)(-4+3x)=1/2

Solution for (-1/3)(-4+3x)=1/2 equation:

(-1/3)(-4+3x)=1/2

We move all terms to the left:

(-1/3)(-4+3x)-(1/2)=0


Domain of the equation: 3)(-4+3x)!=0

We move all terms containing x to the left, all other terms to the right

3x)+3)(!=4

x∈R


We add all the numbers together, and all the variables

(-1/3)(3x-4)-(+1/2)=0

We get rid of parentheses

(-1/3)(3x-4)-1/2=0

We multiply parentheses ..

(-3x^2-1/3*-4)-1/2=0

We calculate fractions


((-3x^2-1*2)/()+()/()=0


We calculate terms in parentheses: +((-3x^2-1*2)/()+()/(), so:

(-3x^2-1*2)/()+()/(

We add all the numbers together, and all the variables

(-3x^2-1*2)/()+1

We multiply all the terms by the denominator


(-3x^2-1*2)+1*()

We add all the numbers together, and all the variables

(-3x^2-1*2)

We get rid of parentheses

-3x^2-1*2

We add all the numbers together, and all the variables

-3x^2-2

Back to the equation:

+(-3x^2-2)


We get rid of parentheses

-3x^2-2=0

a = -3; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-3)·(-2)
Δ = -24
Delta is less than zero, so there is no solution for the equation