(-1/3)(18r-6)=2+6r

Solution for (-1/3)(18r-6)=2+6r equation:

(-1/3)(18r-6)=2+6r

We move all terms to the left:

(-1/3)(18r-6)-(2+6r)=0


Domain of the equation: 3)(18r-6)!=0

r∈R


We add all the numbers together, and all the variables

(-1/3)(18r-6)-(6r+2)=0

We get rid of parentheses

(-1/3)(18r-6)-6r-2=0

We multiply parentheses ..

(-18r^2-1/3*-6)-6r-2=0

We multiply all the terms by the denominator


(-18r^2-1-6r*3*-6)-2*3*-6)=0

We add all the numbers together, and all the variables

(-18r^2-1-6r*3*-6)=0

We get rid of parentheses

-18r^2-6r*3*-1-6=0

We add all the numbers together, and all the variables

-18r^2-6r*3*-7=0

Wy multiply elements

-18r^2-18r^2-7=0

We add all the numbers together, and all the variables

-36r^2-7=0

a = -36; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·(-36)·(-7)
Δ = -1008
Delta is less than zero, so there is no solution for the equation