(-1/3)x+-8=16

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Solution for (-1/3)x+-8=16 equation: 



(-1/3)x+-8=16

We move all terms to the left:

(-1/3)x+-8-(16)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



determiningTheFunctionDomain
(-1/3)x-8-16+=0

We add all the numbers together, and all the variables

(-1/3)x=0

We multiply parentheses

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$

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