(-1/3c)+100=8

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Solution for (-1/3c)+100=8 equation: 



(-1/3c)+100=8

We move all terms to the left:

(-1/3c)+100-(8)=0



Domain of the equation: 3c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(-1/3c)+92=0

We get rid of parentheses

-1/3c+92=0

We multiply all the terms by the denominator


92*3c-1=0

Wy multiply elements

276c-1=0

We move all terms containing c to the left, all other terms to the right

276c=1

c=1/276

c=1/276

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