(-1/4)a-4=7/4-3

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Solution for (-1/4)a-4=7/4-3 equation: 



(-1/4)a-4=7/4-3

We move all terms to the left:

(-1/4)a-4-(7/4-3)=0



Domain of the equation: 4)a!=0

a!=0/1

a!=0

a∈R



We multiply parentheses

-1a^2-4-(7/4-3)=0

We get rid of parentheses

-1a^2-4+3-7/4=0

We multiply all the terms by the denominator


-1a^2*4-7-4*4+3*4=0

We add all the numbers together, and all the variables

-1a^2*4-11=0

Wy multiply elements

-4a^2-11=0

a = -4; b = 0; c = -11;
Δ = b2-4ac
Δ = 02-4·(-4)·(-11)
Δ = -176
Delta is less than zero, so there is no solution for the equation

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