(-1/4)r+6+4r=(3/4)r+2r+7

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Solution for (-1/4)r+6+4r=(3/4)r+2r+7 equation: 



(-1/4)r+6+4r=(3/4)r+2r+7

We move all terms to the left:

(-1/4)r+6+4r-((3/4)r+2r+7)=0



Domain of the equation: 4)r!=0

r!=0/1

r!=0

r∈R





Domain of the equation: 4)r+2r+7)!=0

r!=0/1

r!=0

r∈R



We add all the numbers together, and all the variables

(-1/4)r+4r-((+3/4)r+2r+7)+6=0

We add all the numbers together, and all the variables

4r+(-1/4)r-((+3/4)r+2r+7)+6=0

We multiply parentheses

-1r^2+4r-((+3/4)r+2r+7)+6=0

We multiply all the terms by the denominator


-1r^2*4)r+2r+7)+4r*4)r+2r+7)-((+3+6*4)r+2r+7)=0

We add all the numbers together, and all the variables

-1r^2*4)r+2r+7)+4r*4)r+2r+7)-(27r+2r+7)=0

Wy multiply elements

-16r^4=0

We do not support erpression: r^4

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