(-1/7)r-5=-6

Solution for (-1/7)r-5=-6 equation:

(-1/7)r-5=-6

We move all terms to the left:

(-1/7)r-5-(-6)=0


Domain of the equation: 7)r!=0

r!=0/1

r!=0

r∈R


We add all the numbers together, and all the variables

(-1/7)r+1=0

We multiply parentheses

-1r^2+1=0

a = -1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1)·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*-1}=\frac{-2}{-2}
=1
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*-1}=\frac{2}{-2}
=-1
$