(-10x+58)(x=-3)

Solution for (-10x+58)(x=-3) equation:

(-10x+58)(x=-3)

We move all terms to the left:

(-10x+58)(x-(-3))=0


We calculate terms in parentheses: +(-10x+58)(x-(-3)), so:

-10x+58)(x-(-3)

We add all the numbers together, and all the variables

-10x+58)(x+3

Back to the equation:

+(-10x+58)(x+3)


We multiply parentheses ..

(-10x^2-30x+58x+174)=0

We get rid of parentheses

-10x^2-30x+58x+174=0

We add all the numbers together, and all the variables

-10x^2+28x+174=0

a = -10; b = 28; c = +174;
Δ = b2-4ac
Δ = 282-4·(-10)·174
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-88}{2*-10}=\frac{-116}{-20}
=5+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+88}{2*-10}=\frac{60}{-20}
=-3
$