(-10x+58)x=-3

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Solution for (-10x+58)x=-3 equation:



(-10x+58)x=-3
We move all terms to the left:
(-10x+58)x-(-3)=0
We add all the numbers together, and all the variables
(-10x+58)x+3=0
We multiply parentheses
-10x^2+58x+3=0
a = -10; b = 58; c = +3;
Δ = b2-4ac
Δ = 582-4·(-10)·3
Δ = 3484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3484}=\sqrt{4*871}=\sqrt{4}*\sqrt{871}=2\sqrt{871}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(58)-2\sqrt{871}}{2*-10}=\frac{-58-2\sqrt{871}}{-20} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(58)+2\sqrt{871}}{2*-10}=\frac{-58+2\sqrt{871}}{-20} $

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