(-10x-4)(5x+2)=0

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Solution for (-10x-4)(5x+2)=0 equation: 



(-10x-4)(5x+2)=0

We multiply parentheses ..

(-50x^2-20x-20x-8)=0

We get rid of parentheses

-50x^2-20x-20x-8=0

We add all the numbers together, and all the variables

-50x^2-40x-8=0

a = -50; b = -40; c = -8;
Δ = b2-4ac
Δ = -402-4·(-50)·(-8)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{40}{-100}=-2/5$

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