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(-12x-4)(-8x-3)=2
We move all terms to the left:
(-12x-4)(-8x-3)-(2)=0
We multiply parentheses ..
(+96x^2+36x+32x+12)-2=0
We get rid of parentheses
96x^2+36x+32x+12-2=0
We add all the numbers together, and all the variables
96x^2+68x+10=0
a = 96; b = 68; c = +10;
Δ = b2-4ac
Δ = 682-4·96·10
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-28}{2*96}=\frac{-96}{192} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+28}{2*96}=\frac{-40}{192} =-5/24 $
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