(-16)(t-1.5)(t+1)=14

Solution for (-16)(t-1.5)(t+1)=14 equation:

(-16)(t-1.5)(t+1)=14

We move all terms to the left:

(-16)(t-1.5)(t+1)-(14)=0

We multiply parentheses ..

(-16t+24)(t+1)-14=0

We multiply parentheses ..

(-16t^2-16t+24t+24)-14=0

We get rid of parentheses

-16t^2-16t+24t+24-14=0

We add all the numbers together, and all the variables

-16t^2+8t+10=0

a = -16; b = 8; c = +10;
Δ = b2-4ac
Δ = 82-4·(-16)·10
Δ = 704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{704}=\sqrt{64*11}=\sqrt{64}*\sqrt{11}=8\sqrt{11}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{11}}{2*-16}=\frac{-8-8\sqrt{11}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{11}}{2*-16}=\frac{-8+8\sqrt{11}}{-32}
$