(-2(b+5))/3=-2

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Solution for (-2(b+5))/3=-2 equation: 



(-2(b+5))/3=-2

We move all terms to the left:

(-2(b+5))/3-(-2)=0

We add all the numbers together, and all the variables

(-2(b+5))/3+2=0

We multiply all the terms by the denominator


(-2(b+5))+2*3=0



We calculate terms in parentheses: +(-2(b+5)), so:

-2(b+5)

We multiply parentheses

-2b-10

Back to the equation:

+(-2b-10)



We add all the numbers together, and all the variables

(-2b-10)+6=0

We get rid of parentheses

-2b-10+6=0

We add all the numbers together, and all the variables

-2b-4=0

We move all terms containing b to the left, all other terms to the right

-2b=4

b=4/-2

b=-2

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