(-2)=-2/3(24)+b

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Solution for (-2)=-2/3(24)+b equation: 



(-2)=-2/3(24)+b

We move all terms to the left:

(-2)-(-2/3(24)+b)=0



Domain of the equation: 324+b)!=0

We move all terms containing b to the left, all other terms to the right

b)!=-324

b!=-324/1

b!=-324

b∈R



We add all the numbers together, and all the variables

-(+b-2/324)+(-2)=0

We add all the numbers together, and all the variables

-(+b-2/324)-2=0

We get rid of parentheses

-b-2+2/324=0

We multiply all the terms by the denominator


-b*324+2-2*324=0

We add all the numbers together, and all the variables

-b*324-646=0

Wy multiply elements

-324b-646=0

We move all terms containing b to the left, all other terms to the right

-324b=646

b=646/-324

b=-1+161/162

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