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(-2)=4x^2+2x-18
We move all terms to the left:
(-2)-(4x^2+2x-18)=0
We add all the numbers together, and all the variables
-(4x^2+2x-18)-2=0
We get rid of parentheses
-4x^2-2x+18-2=0
We add all the numbers together, and all the variables
-4x^2-2x+16=0
a = -4; b = -2; c = +16;
Δ = b2-4ac
Δ = -22-4·(-4)·16
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{65}}{2*-4}=\frac{2-2\sqrt{65}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{65}}{2*-4}=\frac{2+2\sqrt{65}}{-8} $
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