(-2+-3r)(6+-1r)=0

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Solution for (-2+-3r)(6+-1r)=0 equation: 



(-2+-3r)(6+-1r)=0

We add all the numbers together, and all the variables

(-3r)(-1r)=0

We multiply parentheses ..

(+3r^2)=0

We get rid of parentheses

3r^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{6}=0$

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