(-2+b/5)=3

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Solution for (-2+b/5)=3 equation: 



(-2+b/5)=3

We move all terms to the left:

(-2+b/5)-(3)=0

We add all the numbers together, and all the variables

(b/5-2)-3=0

We get rid of parentheses

b/5-2-3=0

We multiply all the terms by the denominator


b-2*5-3*5=0

We add all the numbers together, and all the variables

b-25=0

We move all terms containing b to the left, all other terms to the right

b=25

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