(-2-1/7)p=-3

Solution for (-2-1/7)p=-3 equation:

(-2-1/7)p=-3

We move all terms to the left:

(-2-1/7)p-(-3)=0


Domain of the equation: 7)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(-1/7-2)p-(-3)=0

We add all the numbers together, and all the variables

(-1/7-2)p+3=0

We multiply parentheses

-1p^2-2p+3=0

a = -1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·(-1)·3
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-4}{2*-1}=\frac{-2}{-2}
=1
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+4}{2*-1}=\frac{6}{-2}
=-3
$