(-2/(x-2))+(1/(x+4))=(1)

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Solution for (-2/(x-2))+(1/(x+4))=(1) equation: 


D( x )

x+4 = 0

x-2 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:-4) U (-4:2) U (2:+oo)

1/(x+4)-2/(x-2) = 1 // - 1

1/(x+4)-2/(x-2)-1 = 0

(-2*(x+4))/((x-2)*(x+4))+(1*(x-2))/((x-2)*(x+4))+(-1*(x-2)*(x+4))/((x-2)*(x+4)) = 0

1*(x-2)-2*(x+4)-1*(x-2)*(x+4) = 0

8-x^2-x-2*x-10 = 0

-x^2-3*x-2 = 0

-x^2-3*x-2 = 0

-1*(x^2+3*x+2) = 0

x^2+3*x+2 = 0

DELTA = 3^2-(1*2*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-3)/(1*2) or x = (-1^(1/2)-3)/(1*2)

x = -1 or x = -2

-1*(x+2)*(x+1) = 0

(-1*(x+2)*(x+1))/((x-2)*(x+4)) = 0

(-1*(x+2)*(x+1))/((x-2)*(x+4)) = 0 // * (x-2)*(x+4)

-1*(x+2)*(x+1) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x+2 )

x+2 = 0 // - 2

x = -2

x in { -1, -2 }

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