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(-2/3)h=-22
We move all terms to the left:
(-2/3)h-(-22)=0
Domain of the equation: 3)h!=0We add all the numbers together, and all the variables
h!=0/1
h!=0
h∈R
(-2/3)h+22=0
We multiply parentheses
-2h^2+22=0
a = -2; b = 0; c = +22;
Δ = b2-4ac
Δ = 02-4·(-2)·22
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{11}}{2*-2}=\frac{0-4\sqrt{11}}{-4} =-\frac{4\sqrt{11}}{-4} =-\frac{\sqrt{11}}{-1} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{11}}{2*-2}=\frac{0+4\sqrt{11}}{-4} =\frac{4\sqrt{11}}{-4} =\frac{\sqrt{11}}{-1} $
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