(-2/3)x-5+(1/3)x=-4

Solution for (-2/3)x-5+(1/3)x=-4 equation:

(-2/3)x-5+(1/3)x=-4

We move all terms to the left:

(-2/3)x-5+(1/3)x-(-4)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(-2/3)x+(+1/3)x-5-(-4)=0

We add all the numbers together, and all the variables

(-2/3)x+(+1/3)x-1=0

We multiply parentheses

-2x^2+x^2-1=0

We add all the numbers together, and all the variables

-1x^2-1=0

a = -1; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-1)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation