(-2/3)y-(4/7)=(-1/2)

Solution for (-2/3)y-(4/7)=(-1/2) equation:

(-2/3)y-(4/7)=(-1/2)

We move all terms to the left:

(-2/3)y-(4/7)-((-1/2))=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(-2/3)y-(+4/7)-((-1/2))=0

We multiply parentheses

-2y^2-(+4/7)-((-1/2))=0

We get rid of parentheses

-2y^2-4/7-((-1/2))=0

We calculate fractions


-2y^2+()/()+()/()=0

We add all the numbers together, and all the variables

-2y^2+2=0

a = -2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-2)·2
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-2}=\frac{-4}{-4}
=1
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-2}=\frac{4}{-4}
=-1
$