(-2/40)x-(1/40)=(1/40)

Solution for (-2/40)x-(1/40)=(1/40) equation:

(-2/40)x-(1/40)=(1/40)

We move all terms to the left:

(-2/40)x-(1/40)-((1/40))=0


Domain of the equation: 40)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(-2/40)x-(+1/40)-((+1/40))=0

We multiply parentheses

-2x^2-(+1/40)-((+1/40))=0

We get rid of parentheses

-2x^2-1/40-((+1/40))=0

We calculate fractions


-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$