(-22x-5x)+12+2x=15-(13x+2x)+7

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Solution for (-22x-5x)+12+2x=15-(13x+2x)+7 equation: 



(-22x-5x)+12+2x=15-(13x+2x)+7

We move all terms to the left:

(-22x-5x)+12+2x-(15-(13x+2x)+7)=0

We add all the numbers together, and all the variables

(-27x)+2x-(15-(+15x)+7)+12=0

We add all the numbers together, and all the variables

2x+(-27x)-(15-(+15x)+7)+12=0

We get rid of parentheses

2x-27x-(15-(+15x)+7)+12=0



We calculate terms in parentheses: -(15-(+15x)+7), so:

15-(+15x)+7

determiningTheFunctionDomain
-(+15x)+15+7

We add all the numbers together, and all the variables

-(+15x)+22

We get rid of parentheses

-15x+22

Back to the equation:

-(-15x+22)



We add all the numbers together, and all the variables

-25x-(-15x+22)+12=0

We get rid of parentheses

-25x+15x-22+12=0

We add all the numbers together, and all the variables

-10x-10=0

We move all terms containing x to the left, all other terms to the right

-10x=10

x=10/-10

x=-1

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