(-2=5i)(-1+4i)

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Solution for (-2=5i)(-1+4i) equation: 



(-2=5i)(-1+4i)

We move all terms to the left:

(-2-(5i)(-1+4i))=0

We add all the numbers together, and all the variables

(-2-5i(4i-1))=0



We calculate terms in parentheses: +(-2-5i(4i-1)), so:

-2-5i(4i-1)

determiningTheFunctionDomain
-5i(4i-1)-2

We multiply parentheses

-20i^2+5i-2

Back to the equation:

+(-20i^2+5i-2)



We get rid of parentheses

-20i^2+5i-2=0

a = -20; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·(-20)·(-2)
Δ = -135
Delta is less than zero, so there is no solution for the equation

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