(-2a-2b)/c=a

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Solution for (-2a-2b)/c=a equation: 


x in (-oo:+oo)

(-2*a-(2*b))/c = a // - a

(-2*a-(2*b))/c-a = 0

(-2*a-2*b)/c-a = 0

(-2*a-2*b)/c+(-a*c)/c = 0

-2*a-2*b-a*c = 0

-2*a-2*b-(a*c) = 0

(-2*a-2*b-(a*c))/c = 0

(-2*a-2*b-(a*c))/c = 0 // * c

-2*a-2*b-(a*c) = 0

x belongs to the empty set

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