(-2t-8)(8t-2)=0

Solution for (-2t-8)(8t-2)=0 equation:

(-2t-8)(8t-2)=0

We multiply parentheses ..

(-16t^2+4t-64t+16)=0

We get rid of parentheses

-16t^2+4t-64t+16=0

We add all the numbers together, and all the variables

-16t^2-60t+16=0

a = -16; b = -60; c = +16;
Δ = b2-4ac
Δ = -602-4·(-16)·16
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-68}{2*-16}=\frac{-8}{-32}
=1/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+68}{2*-16}=\frac{128}{-32}
=-4
$