(-2x)+9x=6x(-4x)+5

Solution for (-2x)+9x=6x(-4x)+5 equation:

(-2x)+9x=6x(-4x)+5

We move all terms to the left:

(-2x)+9x-(6x(-4x)+5)=0

We add all the numbers together, and all the variables

9x+(-2x)-(6x(-4x)+5)=0

We get rid of parentheses

9x-2x-(6x(-4x)+5)=0


We calculate terms in parentheses: -(6x(-4x)+5), so:

6x(-4x)+5

We multiply parentheses

-24x^2+5

Back to the equation:

-(-24x^2+5)


We add all the numbers together, and all the variables

-(-24x^2+5)+7x=0

We get rid of parentheses

24x^2+7x-5=0

a = 24; b = 7; c = -5;
Δ = b2-4ac
Δ = 72-4·24·(-5)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*24}=\frac{-30}{48}
=-5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*24}=\frac{16}{48}
=1/3
$