(-2x)-40=2-8(x+6)

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Solution for (-2x)-40=2-8(x+6) equation: 



(-2x)-40=2-8(x+6)

We move all terms to the left:

(-2x)-40-(2-8(x+6))=0

We get rid of parentheses

-2x-(2-8(x+6))-40=0



We calculate terms in parentheses: -(2-8(x+6)), so:

2-8(x+6)

determiningTheFunctionDomain
-8(x+6)+2

We multiply parentheses

-8x-48+2

We add all the numbers together, and all the variables

-8x-46

Back to the equation:

-(-8x-46)



We get rid of parentheses

-2x+8x+46-40=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1

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