(-2x+1)(6x+5)=0

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Solution for (-2x+1)(6x+5)=0 equation:



(-2x+1)(6x+5)=0
We multiply parentheses ..
(-12x^2-10x+6x+5)=0
We get rid of parentheses
-12x^2-10x+6x+5=0
We add all the numbers together, and all the variables
-12x^2-4x+5=0
a = -12; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·(-12)·5
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*-12}=\frac{-12}{-24} =1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*-12}=\frac{20}{-24} =-5/6 $

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