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(-2x+1)(6x+5)=0
We multiply parentheses ..
(-12x^2-10x+6x+5)=0
We get rid of parentheses
-12x^2-10x+6x+5=0
We add all the numbers together, and all the variables
-12x^2-4x+5=0
a = -12; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·(-12)·5
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-16}{2*-12}=\frac{-12}{-24} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+16}{2*-12}=\frac{20}{-24} =-5/6 $
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