(-2x+1)(x-3)+25=(-2x+11)(x+2)

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Solution for (-2x+1)(x-3)+25=(-2x+11)(x+2) equation: 



(-2x+1)(x-3)+25=(-2x+11)(x+2)

We move all terms to the left:

(-2x+1)(x-3)+25-((-2x+11)(x+2))=0

We multiply parentheses ..

(-2x^2+6x+x-3)-((-2x+11)(x+2))+25=0



We calculate terms in parentheses: -((-2x+11)(x+2)), so:

(-2x+11)(x+2)

We multiply parentheses ..

(-2x^2-4x+11x+22)

We get rid of parentheses

-2x^2-4x+11x+22

We add all the numbers together, and all the variables

-2x^2+7x+22

Back to the equation:

-(-2x^2+7x+22)



We get rid of parentheses

-2x^2+2x^2+6x+x-7x-3-22+25=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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