(-2x+16)(3x-15)=0

Solution for (-2x+16)(3x-15)=0 equation:

(-2x+16)(3x-15)=0

We multiply parentheses ..

(-6x^2+30x+48x-240)=0

We get rid of parentheses

-6x^2+30x+48x-240=0

We add all the numbers together, and all the variables

-6x^2+78x-240=0

a = -6; b = 78; c = -240;
Δ = b2-4ac
Δ = 782-4·(-6)·(-240)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(78)-18}{2*-6}=\frac{-96}{-12}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(78)+18}{2*-6}=\frac{-60}{-12}
=+5
$