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(-2x+20)(-2x+30)=0
We multiply parentheses ..
(+4x^2-60x-40x+600)=0
We get rid of parentheses
4x^2-60x-40x+600=0
We add all the numbers together, and all the variables
4x^2-100x+600=0
a = 4; b = -100; c = +600;
Δ = b2-4ac
Δ = -1002-4·4·600
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-20}{2*4}=\frac{80}{8} =10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+20}{2*4}=\frac{120}{8} =15 $
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