(-2x+24)(-2x+12)=160

Solution for (-2x+24)(-2x+12)=160 equation:

(-2x+24)(-2x+12)=160

We move all terms to the left:

(-2x+24)(-2x+12)-(160)=0

We multiply parentheses ..

(+4x^2-24x-48x+288)-160=0

We get rid of parentheses

4x^2-24x-48x+288-160=0

We add all the numbers together, and all the variables

4x^2-72x+128=0

a = 4; b = -72; c = +128;
Δ = b2-4ac
Δ = -722-4·4·128
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-56}{2*4}=\frac{16}{8}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+56}{2*4}=\frac{128}{8}
=16
$