(-2x+7)(5-4x)=0

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Solution for (-2x+7)(5-4x)=0 equation:



(-2x+7)(5-4x)=0
We add all the numbers together, and all the variables
(-2x+7)(-4x+5)=0
We multiply parentheses ..
(+8x^2-10x-28x+35)=0
We get rid of parentheses
8x^2-10x-28x+35=0
We add all the numbers together, and all the variables
8x^2-38x+35=0
a = 8; b = -38; c = +35;
Δ = b2-4ac
Δ = -382-4·8·35
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-18}{2*8}=\frac{20}{16} =1+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+18}{2*8}=\frac{56}{16} =3+1/2 $

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