(-3(x+1))/5=x-7

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Solution for (-3(x+1))/5=x-7 equation: 



(-3(x+1))/5=x-7

We move all terms to the left:

(-3(x+1))/5-(x-7)=0

We get rid of parentheses

(-3(x+1))/5-x+7=0

We multiply all the terms by the denominator


(-3(x+1))-x*5+7*5=0



We calculate terms in parentheses: +(-3(x+1)), so:

-3(x+1)

We multiply parentheses

-3x-3

Back to the equation:

+(-3x-3)



We add all the numbers together, and all the variables

(-3x-3)-x*5+35=0

Wy multiply elements

(-3x-3)-5x+35=0

We get rid of parentheses

-3x-5x-3+35=0

We add all the numbers together, and all the variables

-8x+32=0

We move all terms containing x to the left, all other terms to the right

-8x=-32

x=-32/-8

x=+4

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