(-3)+2(4x-13)=(-40x)+7

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Solution for (-3)+2(4x-13)=(-40x)+7 equation: 



(-3)+2(4x-13)=(-40x)+7

We move all terms to the left:

(-3)+2(4x-13)-((-40x)+7)=0

We add all the numbers together, and all the variables

2(4x-13)-((-40x)+7)-3=0

We multiply parentheses

8x-((-40x)+7)-26-3=0



We calculate terms in parentheses: -((-40x)+7), so:

(-40x)+7

We get rid of parentheses

-40x+7

Back to the equation:

-(-40x+7)



We add all the numbers together, and all the variables

8x-(-40x+7)-29=0

We get rid of parentheses

8x+40x-7-29=0

We add all the numbers together, and all the variables

48x-36=0

We move all terms containing x to the left, all other terms to the right

48x=36

x=36/48

x=3/4

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