(-3)=2x2+5(-3)-9

Solution for (-3)=2x2+5(-3)-9 equation:

(-3)=2x^2+5(-3)-9

We move all terms to the left:

(-3)-(2x^2+5(-3)-9)=0

We add all the numbers together, and all the variables

-(2x^2+5(-3)-9)-3=0


We calculate terms in parentheses: -(2x^2+5(-3)-9), so:

2x^2+5(-3)-9

determiningTheFunctionDomain
2x^2-9+5(-3)

We add all the numbers together, and all the variables

2x^2-24

Back to the equation:

-(2x^2-24)


We get rid of parentheses

-2x^2+24-3=0

We add all the numbers together, and all the variables

-2x^2+21=0

a = -2; b = 0; c = +21;
Δ = b2-4ac
Δ = 02-4·(-2)·21
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{42}}{2*-2}=\frac{0-2\sqrt{42}}{-4}
=-\frac{2\sqrt{42}}{-4}
=-\frac{\sqrt{42}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{42}}{2*-2}=\frac{0+2\sqrt{42}}{-4}
=\frac{2\sqrt{42}}{-4}
=\frac{\sqrt{42}}{-2}
$