(-3)=3n-2(n+3)

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Solution for (-3)=3n-2(n+3) equation: 



(-3)=3n-2(n+3)

We move all terms to the left:

(-3)-(3n-2(n+3))=0

We add all the numbers together, and all the variables

-(3n-2(n+3))-3=0



We calculate terms in parentheses: -(3n-2(n+3)), so:

3n-2(n+3)

We multiply parentheses

3n-2n-6

We add all the numbers together, and all the variables

n-6

Back to the equation:

-(n-6)



We get rid of parentheses

-n+6-3=0

We add all the numbers together, and all the variables

-1n+3=0

We move all terms containing n to the left, all other terms to the right

-n=-3

n=-3/-1

n=+3

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