(-3+4i)(-3-4i)=0

Solution for (-3+4i)(-3-4i)=0 equation:

(-3+4i)(-3-4i)=0

We add all the numbers together, and all the variables

(4i-3)(-4i-3)=0

We multiply parentheses ..

(-16i^2-12i+12i+9)=0

We get rid of parentheses

-16i^2-12i+12i+9=0

We add all the numbers together, and all the variables

-16i^2+9=0

a = -16; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-16)·9
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-16}=\frac{-24}{-32}
=3/4
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-16}=\frac{24}{-32}
=-3/4
$