(-3-i)(2-2i)=0

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Solution for (-3-i)(2-2i)=0 equation:


Simplifying
(-3 + -1i)(2 + -2i) = 0

Multiply (-3 + -1i) * (2 + -2i)
(-3(2 + -2i) + -1i * (2 + -2i)) = 0
((2 * -3 + -2i * -3) + -1i * (2 + -2i)) = 0
((-6 + 6i) + -1i * (2 + -2i)) = 0
(-6 + 6i + (2 * -1i + -2i * -1i)) = 0
(-6 + 6i + (-2i + 2i2)) = 0

Combine like terms: 6i + -2i = 4i
(-6 + 4i + 2i2) = 0

Solving
-6 + 4i + 2i2 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-3 + 2i + i2) = 0

Factor a trinomial.
2((-3 + -1i)(1 + -1i)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-3 + -1i)' equal to zero and attempt to solve: Simplifying -3 + -1i = 0 Solving -3 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1i = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1i = 0 + 3 -1i = 0 + 3 Combine like terms: 0 + 3 = 3 -1i = 3 Divide each side by '-1'. i = -3 Simplifying i = -3

Subproblem 2

Set the factor '(1 + -1i)' equal to zero and attempt to solve: Simplifying 1 + -1i = 0 Solving 1 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1i = 0 + -1 -1i = 0 + -1 Combine like terms: 0 + -1 = -1 -1i = -1 Divide each side by '-1'. i = 1 Simplifying i = 1

Solution

i = {-3, 1}

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