(-3/2)m=12

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Solution for (-3/2)m=12 equation: 



(-3/2)m=12

We move all terms to the left:

(-3/2)m-(12)=0



Domain of the equation: 2)m!=0

m!=0/1

m!=0

m∈R



We multiply parentheses

-3m^2-12=0

a = -3; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-3)·(-12)
Δ = -144
Delta is less than zero, so there is no solution for the equation

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