(-3/4)(x-4)=5+2x

Solution for (-3/4)(x-4)=5+2x equation:

(-3/4)(x-4)=5+2x

We move all terms to the left:

(-3/4)(x-4)-(5+2x)=0


Domain of the equation: 4)(x-4)!=0

x∈R


We add all the numbers together, and all the variables

(-3/4)(x-4)-(2x+5)=0

We get rid of parentheses

(-3/4)(x-4)-2x-5=0

We multiply parentheses ..

(-3x^2-3/4*-4)-2x-5=0

We multiply all the terms by the denominator


(-3x^2-3-2x*4*-4)-5*4*-4)=0

We add all the numbers together, and all the variables

(-3x^2-3-2x*4*-4)=0

We get rid of parentheses

-3x^2-2x*4*-3-4=0

We add all the numbers together, and all the variables

-3x^2-2x*4*-7=0

Wy multiply elements

-3x^2-8x^2-7=0

We add all the numbers together, and all the variables

-11x^2-7=0

a = -11; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·(-11)·(-7)
Δ = -308
Delta is less than zero, so there is no solution for the equation