(-3/5)x-9=-27

Solution for (-3/5)x-9=-27 equation:

(-3/5)x-9=-27

We move all terms to the left:

(-3/5)x-9-(-27)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(-3/5)x+18=0

We multiply parentheses

-3x^2+18=0

a = -3; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·(-3)·18
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*-3}=\frac{0-6\sqrt{6}}{-6}
=-\frac{6\sqrt{6}}{-6}
=-\frac{\sqrt{6}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*-3}=\frac{0+6\sqrt{6}}{-6}
=\frac{6\sqrt{6}}{-6}
=\frac{\sqrt{6}}{-1}
$