(-3/7)(m-9)=3+6m

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Solution for (-3/7)(m-9)=3+6m equation:



(-3/7)(m-9)=3+6m
We move all terms to the left:
(-3/7)(m-9)-(3+6m)=0
Domain of the equation: 7)(m-9)!=0
m∈R
We add all the numbers together, and all the variables
(-3/7)(m-9)-(6m+3)=0
We get rid of parentheses
(-3/7)(m-9)-6m-3=0
We multiply parentheses ..
(-3m^2-3/7*-9)-6m-3=0
We multiply all the terms by the denominator
(-3m^2-3-6m*7*-9)-3*7*-9)=0
We add all the numbers together, and all the variables
(-3m^2-3-6m*7*-9)=0
We get rid of parentheses
-3m^2-6m*7*-3-9=0
We add all the numbers together, and all the variables
-3m^2-6m*7*-12=0
Wy multiply elements
-3m^2-42m^2-12=0
We add all the numbers together, and all the variables
-45m^2-12=0
a = -45; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-45)·(-12)
Δ = -2160
Delta is less than zero, so there is no solution for the equation

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