(-3h+8)(-2h+8)=0

Solution for (-3h+8)(-2h+8)=0 equation:

(-3h+8)(-2h+8)=0

We multiply parentheses ..

(+6h^2-24h-16h+64)=0

We get rid of parentheses

6h^2-24h-16h+64=0

We add all the numbers together, and all the variables

6h^2-40h+64=0

a = 6; b = -40; c = +64;
Δ = b2-4ac
Δ = -402-4·6·64
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8}{2*6}=\frac{32}{12}
=2+2/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8}{2*6}=\frac{48}{12}
=4
$